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x^2-9x/25-16=0
We multiply all the terms by the denominator
x^2*25-9x-16*25=0
We add all the numbers together, and all the variables
x^2*25-9x-400=0
Wy multiply elements
25x^2-9x-400=0
a = 25; b = -9; c = -400;
Δ = b2-4ac
Δ = -92-4·25·(-400)
Δ = 40081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{40081}}{2*25}=\frac{9-\sqrt{40081}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{40081}}{2*25}=\frac{9+\sqrt{40081}}{50} $
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